Yahoo Answers: Answers and Comments for In a carnival there are 95 red balls and 30 blue balls. you get to pick 3 random balls without putting them back,? [Mathematics]
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From Anonymous
enSG
Sat, 25 May 2019 15:38:42 +0000
3
Yahoo Answers: Answers and Comments for In a carnival there are 95 red balls and 30 blue balls. you get to pick 3 random balls without putting them back,? [Mathematics]
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From Mike G: P(3 Red Balls) = 95/125*94/124*93/123
= 0.4356...
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https://sg.answers.yahoo.com/question/index?qid=20190525153842AAkqMdm
Sat, 25 May 2019 20:06:28 +0000
P(3 Red Balls) = 95/125*94/124*93/123
= 0.4356
P(Blue Ball) = 10.4356
= 0.5644

From Morningfox: The probability of getting all red balls is (9...
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Sat, 25 May 2019 15:49:01 +0000
The probability of getting all red balls is (95/125) * (94/124) * ( 93/123) = 43.56%. So the prob. of getting a blue ball is 100%  43.56% = 56.44%.

From A.J.: Easiest way is assuming one or more blue balls...
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Sat, 25 May 2019 15:47:06 +0000
Easiest way is assuming one or more blue balls get a prize since nothing stated about extra blue ones.
All red is the complement to one or more blue.
3 red
95+30=125 total
95/125 first pick
94/124 second pick
93/123 third pick
(95 x 94 x 93) / (125 x 124 x 123) is probability of 3 red
1 ((95 x 94 x 93) / (125 x 124 x 123)) is probability of 1 or more blue
1 830490/1906500
1 0.43 56097 56097...
0.56439

From Captain Matticus, LandPiratesInc: Again, examine your possibilities:
0 blue bal...
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Sat, 25 May 2019 15:45:12 +0000
Again, examine your possibilities:
0 blue balls
1 blue ball
2 blue balls
3 blue balls
The only way you lose is if you get no blue balls
95 red balls + 30 blue balls = 125 balls
95/125 chance of pulling a red ball on the first try
94/124 chance of pulling a red ball on the 2nd try
93/123 chance of pulling a red ball on the 3rd try
The chances of pulling 3 red balls is:
(95/125) * (94/124) * (93/123) =>
(19/25) * (47/62) * (31/41) =>
19 * 47 * 31 / (25 * 62 * 41) =>
19 * (39 + 8) * (39  8) / (25 * 2 * 31 * 41) =>
19 * (39^2  8^2) / (50 * (36  5) * (36 + 5)) =>
19 * ((40  1)^2  64) / (50 * (36^2  5^2)) =>
19 * (1600  80 + 1  64) / (50 * (1296  25)) =>
19 * (1600  143) / (50 * 1271) =>
19 * 1457 / (50 * (1270 + 1)) =>
(20  1) * 1457 / (50 * 2 * 635 + 50) =>
(29140  1457) / (100 * 635 + 50) =>
(28140  457) / (63500 + 50) =>
(27740  57) / 63550 =>
(27690  7) / 63550 =>
27683 / 63550
1  (27683 / 63550) =>
(63550  27683) / 63550 =>
(36550  683) / 63550 =>
(39950  83) / 63550 =>
(39870  3) / 63550 =>
39867 / 63550