Yahoo Answers: Answers and Comments for Prove that (2n)!/n!=1x3x5...............(21)x2^n ? [Mathematics]
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https://sg.answers.yahoo.com/question/index?qid=20121204182749AADlVXx
From rdx
enSG
Tue, 04 Dec 2012 18:27:49 +0000
3
Yahoo Answers: Answers and Comments for Prove that (2n)!/n!=1x3x5...............(21)x2^n ? [Mathematics]
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https://sg.answers.yahoo.com/question/index?qid=20121204182749AADlVXx
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From Anonymous: (2n)! = (2n) X (2n1) X (2n2) X (2n3) X (2n...
https://sg.answers.yahoo.com/question/index?qid=20121204182749AADlVXx
https://sg.answers.yahoo.com/question/index?qid=20121204182749AADlVXx
Wed, 05 Dec 2012 03:42:02 +0000
(2n)! = (2n) X (2n1) X (2n2) X (2n3) X (2n4) X ... X 3 X 2 X 1
= (2n1) X (2n3) X (2n5) X ... X 3 X 1
X 2(n) X 2(n1) X 2(n2) X 2(n3) X ...X 2 X 1
= (2n1) X (2n3) X (2n5) X ... X3X1
X 2^n X n!
So (2n)!/n! is 2^n times (2n1)X(2n3)X...X3X1

From Anonymous: It looks like Yahoo cut of your formula. Pleas...
https://sg.answers.yahoo.com/question/index?qid=20121204182749AADlVXx
https://sg.answers.yahoo.com/question/index?qid=20121204182749AADlVXx
Wed, 05 Dec 2012 02:44:28 +0000
It looks like Yahoo cut of your formula. Please add the rest of it. You need to include some spacee. If a "word" is too long it won't all be shown.