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lil asked in Science & MathematicsPhysics · 1 month ago

physics problem?

a submarine dives to a depth of 500 m. The density of seawater is 1025 kg/m^3.

 how much absolute total pressure must it’s hull be able to withstand-how many times larger is this pressure than the pressure at the surface-

1 Answer

  • 1 month ago
    Favourite answer

    pressure is the weight of a 1 m² column of water.

    in this case, volume is 500 x 1 = 500 m³

    mass is 1025 kg/m³ x 500 m³ = 512500 kg

    weight = 512500 kg x 9.8 N/kg = 5023000 N

    pressure = 5023000 N/m² = 5023000 Pa = 5023 kPa

    add air pressure of 101 kPa to that to get absolute pressure of 5124 kPa

    but hull has internal air pressure, so pressure differential the hull sees is actually 5023 kPa

    ratio is 5124/101 = 50.7

    or  5023/101 = 49.7

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