probability math question?
Eight students will be taking the courses shown in the following table in Semester
Arnold: PHYS101, MATH101, ENGL101
Bill: PHYS101, CHEM101, ECON101
Carol: CHEM101, MGMT101
Denise: STAT101, ECON101
Eleanor: MATH101, MGMT101
Fred: PHYS101, CHEM101, MATH101
George: MGMT101, STAT101
Ingrid: ENGL101, STAT101
How many time periods must be allowed for these students to take the courses they want without conflict?
- jacob sLv 71 month ago
Clearly we see 8 students and 7 subjects.
Total numbers of time periods must be allowed for these students to take the courses they want without conflict
conflict equals = 8!/(7! 8 - 7!) - 8!/(7!1!) = (8 x 7!)/7! = 8
y = Frequency
x = subject
Frequency 3 3 2 3 2 3 3
PHYS101 = 3
MATH101 = 3
ENGL 101 = 2
CHEM101 = 3
ECON101 = 2
MGMT101 = 3
STAT101 = 3
Clearly see that the subjects have equal frequency = 3 as ENGL 101 and ECON101 have frequency = 2 which is indicated by the the above information ( please graph it Frequency vs subject) you will see the increments and decrements of the period according to the student.