Algebra help? (picture below) please show good details?

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  • 1 month ago

    The coordinates of A=(1,4); B=(2,5)

    =>

    AB=sqr[(2-1)^2+(5-4)^2]=sqr(2)

  • 1 month ago

    Distance between A(1, 4) and B(2, 5):

    sqrt(2) ≈ 1.41421

  • 1 month ago

    The two-point A(1,4) and B(2,5)

    the distance equation AB=sqrt{(2-1)^2+(5-4)^2}=sqrt(1+1)=sqrt 2

  • 1 month ago

    This is the same thing as your question from 4 hours ago, only using different numbers.

    The distance equation between two points, derived from the Pythagorean Theorem is:

    d = √[(x₁ - x₂)² + (y₁ - y₂)²]

    This is an equation you will be expected to memorize.

    Using the points (1, 4) and (2, 5), substitute and solve for d:

    d = √[(1 - 2)² + (4 - 5)²]

    d = √[(-1)² + (-1)²]

    d = √(1 + 1)

    d = √2

    Normally I would leave it like this but since you are asked to round to 2DP, using a calculator to get a decimal approximation gives me:

    d = 1.41 units

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  • 1 month ago

    A (1 ; 4)   B (2 ; 5)

    Distance AB

    xAB = xB - xA = 2 - 1 = 1

    yAB = yB - yA = 5 - 4 = 1

    AB² = xAB² + yAB²

    AB² = (1)² + (1)²

    AB² = 2

    AB = √2

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