calc question?

Question

he height, h, in meters of a dropped object after t seconds, can be represented by h (t)=-4.9t^2+346.   What is the instantaneous velocity of the object one second after it is dropped?

 

Answer 1

Instantaneous velocity at time t is given by dh(t)/dt

h = -4.9t² + 346

dh/dt = -9.8t

dh(1)/dt = -9.8 m/s

(negative sign indicates movement is in the negative h direction)