he height, h, in meters of a dropped object after t seconds, can be represented by h (t)=-4.9t^2+346. What is the instantaneous velocity of the object one second after it is dropped?
- TomVLv 71 month ago
Instantaneous velocity at time t is given by dh(t)/dt
h = -4.9t² + 346
dh/dt = -9.8t
dh(1)/dt = -9.8 m/s
(negative sign indicates movement is in the negative h direction)