solution is prepared by diluting 25.00ml of a 0.308M solution of NiCl2 to the final volume of 0.500L whatis consecration of NiCl2 insolution?

1 Answer

  • 2 months ago

    M1V1 = M2V2

    (0.308 mol/L) (0.02500 L) = (x) (0.500 L)

    x = 0.0154 M

    You can also set it up like this:

    (0.308 mol/L) (25.00 mL) = (x) (500. mL)

    The volumes can be any unit you wish, they just have to be the same units for V1 and V2.

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