solution is prepared by diluting 25.00ml of a 0.308M solution of NiCl2 to the final volume of 0.500L whatis consecration of NiCl2 insolution?
- ChemTeamLv 72 months ago
M1V1 = M2V2
(0.308 mol/L) (0.02500 L) = (x) (0.500 L)
x = 0.0154 M
You can also set it up like this:
(0.308 mol/L) (25.00 mL) = (x) (500. mL)
The volumes can be any unit you wish, they just have to be the same units for V1 and V2.
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