Factor this number?

Question

X^2y - 2x^2 + 3y - 6

My workbook says the answer is (y - 2)(x^3 + 3) i think its wrong.

Answer 1

Favourite answer

Since the workbook answer has a x^3 term, and no terms in x or x^2, then the expanded form must also have terms in x^3 and no terms in x or x^2.  So you're right.

The correct answer is (y-2) ( x^2 + 3)

Answer 2

(x^2)y-2x^2+3y-6=

(x^2)(y-2)+3(y-2)=

(y-2)(x^2+3)

Answer 3

x^2y - 2x^2 + 3y - 6

x^2(y - 2) + 3(y - 2) =

(x^2 + 3)(y - 2)

The workbook's answer is correct.

Answer 4

x²y - 2x² + 3y - 6 => x²y + 3y - 2x² - 6

so, y(x² + 3) - 2(x² + 3)

i.e. (y - 2)(x² + 3)

The workbook is wrong.

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Answer 5

x^2 y - 2 x^2 + 3 y - 6

= (x^2 + 3) (y - 2)

Answer 6

x^2y - 2x^2 + 3y - 6

=x^2(y - 2) + 3(y - 2)

= (y - 2)(x^2 + 3) Answer//

The answer in your book is wrong...

Source(s): https://www.wolframalpha.com/input/?i=factor+x%5E2...

Answer 7

You can't have an x³ factor if the highest x terms are x².

x²y - 2x² + 3y - 6

If we factor out an x² from the first 2 terms and a 3 from the last two terms we get:

x²(y - 2) + 3(y - 2)

Now we can factor a (y - 2) from that to get:

(x² + 3)(y - 2)

That's your factored form.