A certain bacteria double its number in 6 hours. There are 20 bacteria initially. How many bacteria are there after 48 hours?

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  • ?
    Lv 7
    2 months ago

    B(t) = B(0) x 2^(t/d)

    so, B(t) = 20 x 2^(t/6)

    Then, with t = 48 we have:

    B(t) = 20 x 2^(48/6) => 20 x 2⁸

    i.e. 20 x 256 = 5120

    :)>

  • 2 months ago

    A certain bacteria doubles its number in 6 hours. 

    There are 20 bacteria initially. 

     

    20, 40, 80, 160, 320, 640, 1280, 2560, ....

    There are 2560 bacteria are after 48 hours.

  • rotchm
    Lv 7
    2 months ago

    Do it step by step.

    Now: 20

    At 6h = 20*2 = 40

    At 12h = 40 * 2 = ?

    At 18h = above * 2 = ?

    At 24h = ...

    Do it up to At 48 h = your answer.

    What do you finally get?

    Answer that and then we will take it from there (we will show you how to obtain the general formula if needed). 

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