# A certain bacteria double its number in 6 hours. There are 20 bacteria initially. How many bacteria are there after 48 hours?

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- ?Lv 72 months ago
B(t) = B(0) x 2^(t/d)

so, B(t) = 20 x 2^(t/6)

Then, with t = 48 we have:

B(t) = 20 x 2^(48/6) => 20 x 2⁸

i.e. 20 x 256 = 5120

:)>

- KrishnamurthyLv 72 months ago
A certain bacteria doubles its number in 6 hours.

There are 20 bacteria initially.

20, 40, 80, 160, 320, 640, 1280, 2560, ....

There are 2560 bacteria are after 48 hours.

- rotchmLv 72 months ago
Do it step by step.

Now: 20

At 6h = 20*2 = 40

At 12h = 40 * 2 = ?

At 18h = above * 2 = ?

At 24h = ...

Do it up to At 48 h = your answer.

What do you finally get?

Answer that and then we will take it from there (we will show you how to obtain the general formula if needed).

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