Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

# math pre calc 11 question?

Jon left on a trip to the lake towing a trailer; his speed was 75 km/hr. Jim left two hours later, driving at a speed of 100km/hr. How long did it take Jim to catch up to Jon?

I know the answer is 6 hours but I am unsure as to how to get to this as my work does not equal to this answer. thank you!

Relevance
• 2 months ago

In 2 hrs, Jon has traveled a distance=75(2)=150 km. Now, Jim starts

to catch up Jon at 100 km/hr. The time taken=150/(100-75)=6 hrs for

Jim to reach Jon.

• 2 months ago

Jon has traveled for 2 hours at 75 mph, so he has a 150 mile headstart.

Jim is driving 25 mph faster, so he will close the gap in 150/25 = 6 hours.

6 hours

• 2 months ago

Jon left on a trip to the lake towing a trailer; his speed was 75 km/hr.

Jim left two hours later, driving at a speed of 100 km/hr.

75x = 100(x - 2)

x = 8

It took 6 hours for Jim to catch up to Jon.

• 2 months ago

The two distances traveled must be equal.

Let t be the number of hours Jim traveled.

Let (t + 2) be the number of hours Jon traveled.

Then:

100t = 75(t + 2)

100t = 75t + 150

25t = 150

t = 6 hours