Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

math pre calc 11 question?

Jon left on a trip to the lake towing a trailer; his speed was 75 km/hr. Jim left two hours later, driving at a speed of 100km/hr. How long did it take Jim to catch up to Jon?

I know the answer is 6 hours but I am unsure as to how to get to this as my work does not equal to this answer. thank you!

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  • 2 months ago

    In 2 hrs, Jon has traveled a distance=75(2)=150 km. Now, Jim starts

    to catch up Jon at 100 km/hr. The time taken=150/(100-75)=6 hrs for

    Jim to reach Jon.

  • 2 months ago

    Jon has traveled for 2 hours at 75 mph, so he has a 150 mile headstart.

    Jim is driving 25 mph faster, so he will close the gap in 150/25 = 6 hours.

    Answer:

    6 hours

  • 2 months ago

    Jon left on a trip to the lake towing a trailer; his speed was 75 km/hr. 

    Jim left two hours later, driving at a speed of 100 km/hr. 

    75x = 100(x - 2)

    x = 8

    It took 6 hours for Jim to catch up to Jon.

  • 2 months ago

    The two distances traveled must be equal.

    Let t be the number of hours Jim traveled.

    Let (t + 2) be the number of hours Jon traveled.

    Then:

    100t = 75(t + 2)

    100t = 75t + 150

    25t = 150

    t = 6 hours

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  • 75 * (t + 2) = 100 * t

    We want to know the time that Jim is driving

    75t + 150 = 100t

    150 = 25t

    6 = t

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