math pre calc 11 question?
Jon left on a trip to the lake towing a trailer; his speed was 75 km/hr. Jim left two hours later, driving at a speed of 100km/hr. How long did it take Jim to catch up to Jon?
I know the answer is 6 hours but I am unsure as to how to get to this as my work does not equal to this answer. thank you!
- PinkgreenLv 72 months ago
In 2 hrs, Jon has traveled a distance=75(2)=150 km. Now, Jim starts
to catch up Jon at 100 km/hr. The time taken=150/(100-75)=6 hrs for
Jim to reach Jon.
- PuzzlingLv 72 months ago
Jon has traveled for 2 hours at 75 mph, so he has a 150 mile headstart.
Jim is driving 25 mph faster, so he will close the gap in 150/25 = 6 hours.
- KrishnamurthyLv 72 months ago
Jon left on a trip to the lake towing a trailer; his speed was 75 km/hr.
Jim left two hours later, driving at a speed of 100 km/hr.
75x = 100(x - 2)
x = 8
It took 6 hours for Jim to catch up to Jon.
- stanschimLv 72 months ago
The two distances traveled must be equal.
Let t be the number of hours Jim traveled.
Let (t + 2) be the number of hours Jon traveled.
100t = 75(t + 2)
100t = 75t + 150
25t = 150
t = 6 hours
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- 2 months ago
75 * (t + 2) = 100 * t
We want to know the time that Jim is driving
75t + 150 = 100t
150 = 25t
6 = t