Johan asked in Science & MathematicsMathematics · 2 months ago

# Equation using BEDMAS?

Can anyone help me solve this equation it is a BEDMAS problem but I cannot seem to solve it and please kindly explain it is attached below as a .png.

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• 2 months ago

When I was at school it called BODMAS Brackets, orders (squares, powers etc) division, multiplication, addition, subtraction.

• 2 months ago

In order to evaluate that expression (it's not an equation because there is no equal sign), just follow the order of operations.

The first thing to do are the things in brackets. We have some explicit brackets (parentheses) in the numerator, so first evaluate that expression:

10 * 2 - √25

In this expression we start with "exponents" which means items raised to a power and items with roots. So take the square root:

10 * 2 - 5

Next do the multiplication:

20 - 5

Then the subtraction:

15

So the expression gets reduced to:

15²

-----------

3 - 2 * 4

In a fraction like this, there's an implied grouping of the numerator and the denominator. So we have to evaluate each of those before dividing.

Numerator:

15² = 225

Denominator:

3 - 2 * 4

Do the multiplication first:

3 - 8

Then the subtraction:

-5

So the fraction gets reduced to:

225

-----

-5

Finally do the division:

225 / -5

= -45

-45

• Jeremy
Lv 6
2 months ago

It is NOT an equation. It is an expression.

(10 * 2 - √25)² / (3 - 2 * 4) = (20 - 5)² / (3 - 8) = 15² / (-5) = -225 / 5 = -45 <=== Answer

• ?
Lv 7
2 months ago

{[10*2-sqr(25)]^2}/(3-2*4)

=

{[20-5]^2}/(3-8)

=

{15*15}/(-5)

=

-3*15

=

-45

• 2 months ago

(20 - 5)^2/(3 - 8) = 15^2/(-5) 225/(-5) = -45

Please not that this is an expression rather than an equation. As such, you need to evaluate it, not solve it.

• 2 months ago

Order of operations:

[10 * 2 - √(25)]² / (3 - 2 * 4)

The first step is to complete anything in parenthesis.  The entire numerator of your fraction and the entire denominator of the fraction are in their own sets of parenthesis so we have to simplify them each, first, then do the final division.

In the numerator, we do exponents first.  The square root falls in the exponent rule so that is done first.  Then the multiplication, then the subtraction, then finally the exponent outside of the parenthesis:

(10 * 2 - 5)² / (3 - 2 * 4)

(20 - 5)² / (3 - 2 * 4)

15² / (3 - 2 * 4)

225 / (3 - 2 * 4)

For the denominator, we do the multiplication first, then the subtraction:

225 / (3 - 8)

225 / (-5)

Finally, the division:

-45

• 2 months ago

(10 ⋅ 2 - sqrt 25)^2 / (3 - 2 ⋅ 4) = 225/(-5) = -45

• 2 months ago

Canada and New Zealand use BEDMAS, standing for Brackets, Exponents, Division/Multiplication, Addition/Subtraction.

(10•2 – √25)² / (3 – 2•4)

(note that second set of brackets are implied by the division line.

brackets first

(10•2 – √25)

then exponents

(10•2 – 5)     (principle root only, see below)

then multip.

(20 – 5)

then subtract

(15)

now outside the brackets, the square

15² = 225

now the other bracket

(3 – 2•4)

multiply first

(3 – 8)

then subtract

(–5)

now the original expression is

225/–5

divide

other root of √25 is –5

redoing with that

(10•2 – (–5))

(20 + 5)

(25)

25² = 625

625/–5

• fcas80
Lv 7
2 months ago

10*2 = 20

2*4 = 8

(20 - √ 25) ^2 = (20 -5)^2 = 15^2 = 225

3 - 2*4 = 3 - 8 = - 5

225/-5 = -45

• 2 months ago

Inside top parentheses, multiply first then subtract.

10 • 2 = 20, √25 = 5,

so it's 20 - 5 = 15

Then square it:  225

On bottom do multiply first; 2 • 4 = 8 and 3 - 8 = -5

So 225 / (-5) = -45