# math help? simple algebra?

This is part a:

Lida made some chocolate chip cookies. She gave 2/5 of her cookies to gina and then gave 1/2 of the remaining cookies to Jim. At that point, Lida had 24 cookies left. how many chocolate cookies did she have at first.

I solved part a, she had 80 cookies at first. Part B is where I need help..

part b:

write an equation that corresponds to this situation and solve it algebraically. define your variables

### 2 Answers

- KrishnamurthyLv 74 weeks ago
Part a:

Lida made some chocolate chip cookies.

She gave 2/5 of her cookies to gina and then gave 1/2 of the remaining cookies to Jim.

2/5 + 3/10 = 7/10

At that point, Lida had 24 cookies left.

how many chocolate cookies did she have at first.

she had 80 cookies at first.

part b:

write an equation that corresponds to this situation

and solve it algebraically.

define your variables

3/10 = 24 cookies

The total amount equals 80 cookies.

- MichaelLv 71 month ago
She gave 2/5 of her cookies to gina

Therefor Lida had 3/5 of her cookies remainingand then gave 1/2 of the remaining cookies to Jim.

1/2 of 3/5 is 3/10

There for Lida had 3/10 of her cookies remaining

(3/10)c = 24

Multiply both sides by 10/3

c = 80 <––––

------------------------

Equation

c = starting number of cookies

(c - (2/5)c) * (1/2) = 24

Combine like terms

(3/5)c * (1/2) = 24

Multiply both sides by 2

(3/5)c = 48

Multiply both sides by 5/3

c = 80 <––––––