Anonymous
Anonymous asked in Education & ReferenceHomework Help · 1 month ago

math help? simple algebra?

This is part a:

Lida made some chocolate chip cookies. She gave 2/5 of her cookies to gina and then gave 1/2 of the remaining cookies to Jim. At that point, Lida had 24 cookies left. how many chocolate cookies did she have at first.

I solved part a, she had 80 cookies at first. Part B is where I need help..

part b:

write an equation that corresponds to this situation and solve it algebraically. define your variables

2 Answers

Relevance
  • 4 weeks ago

    Part a:

    Lida made some chocolate chip cookies. 

    She gave 2/5 of her cookies to gina and then gave 1/2 of the remaining cookies to Jim. 

    2/5 + 3/10 = 7/10

    At that point, Lida had 24 cookies left. 

    how many chocolate cookies did she have at first.

     she had 80 cookies at first. 

    part b:

    write an equation that corresponds to this situation 

    and solve it algebraically. 

    define your variables

    3/10 = 24 cookies

    The total amount equals 80 cookies.

  • 1 month ago

    She gave 2/5 of her cookies to gina 

    Therefor Lida had 3/5 of her cookies remainingand then gave 1/2 of the remaining cookies to Jim.

    1/2 of 3/5 is 3/10 

    There for Lida had 3/10 of her cookies remaining

    (3/10)c = 24

    Multiply both sides by 10/3

    c = 80 <––––

    ------------------------

    Equation

    c = starting number of cookies

    (c - (2/5)c) * (1/2) = 24

    Combine like terms

    (3/5)c * (1/2) = 24

    Multiply both sides by 2

    (3/5)c = 48

    Multiply both sides by 5/3

    c = 80 <––––––

Still have questions? Get answers by asking now.