Kat asked in Science & MathematicsChemistry · 4 weeks ago

 Kc for the reaction N2(g) + O2(g) ⇀↽ 2 NO(g) at 1200◦C is 1 × 10−5 What is the equilibrium molar concentration of NO?

The equilibrium constant Kc for the reaction

N2(g) + O2(g) ⇀↽ 2 NO(g)

at 1200◦C is 1 × 10−5

. What is the equilibrium molar concentration of NO in a 12 L

reaction vessel that initially held 0.076 mol

N2 and 0.427 mol O2?

Answer in units of mol/L

1 Answer

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  • 4 weeks ago

    Kc = [NO]^2 / [N2][O2] = 1X10^-5

    Set up an ICE table:

    ...................[N2]...............[O2]...........[NO]

    initial......6.33X10^-3....0.0356...........0

    Change.......-x...................-x..............+2x

    Equil.....6.33X10^-3-x....0.0356-x......2x

    Because K is very small, initially assume that x will be insignificant compared to 6.33X10^-3 and to 0.0356. Then,

    Kc = 1X10^-5 = x^2 / (6.33X10^-3)(0.0356)

    x = 4.7X10^-5 M

    [NO] = 2x = 9.5X10^-5 M

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