# What's the answer to this calculus problem?

there's a attached picture... thanks

### 1 Answer

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- nyphdinmdLv 71 month ago
THis is pretty much using the definition of partial derivative

Let D/Dx = partial derivative wrt to x and so on

Df/Dx = 8*x/(x^2 - y^2) Df/Dy = -8y/(x^2 - y^2)

D(Df/Dx)/Dy = 16xy/(x^2 - y^2)^2 D(Df/Dy)/Dx = 16xy/(x^2 - y^2)

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