Chemistry Problem?

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  • 4 weeks ago

    2.

    (5.17 g Ni3(PO4)2) / (366.0229 g Ni3(PO4)2/mol) x

    (3 mol NiCl2 / 1 mol Ni3(PO4)2) x (129.5994 g NiCl2/mol) / (0.655) = 8.38 g NiCl2

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