Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

13.10 The molality of Na2CO3 in the solution is 0.200m. What is the mole fraction of Na2CO3 in this solution?

What mass of Na2CO3 must you add to 125 g of water to prepare 0.200m Na2CO3?

mass= 2.65g

QUESTION:

The molality of Na2CO3 in the solution is 0.200m. What is the mole fraction of Na2CO3 in this solution?

Mole fraction = ??

1 Answer

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  • 1 month ago
    Favourite answer

    (0.200 mol/kg) x (0.125 kg) x (105.9884 g Na2CO3/mol) = 2.65 g Na2CO3

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    0.200m = 0.200 mol/kg

    (1000 g H2O) / (18.01532 g H2O/mol) = 55.508 mol H2O

    (0.200 mol solute) / (0.200 mol solute + 55.508 mol H2O) =

    0.00359 (the mole fraction of solute)

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