Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

Circle standard form question?

Tangent to the x axis at (2,0), and the radius is 3

2 Answers

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  • 1 month ago

    If the x-axis is a tangent, the circle touches at (2, 0)

    If the radius is 3, then (2, 3) is the centre

    so, (y - 3)² + (x - 2)² = 3²

    Expanding gives, y² - 6y + x² - 4x + 13 = 9

    i.e. y² - 6y + x² - 4x + 4 = 0  

    A sketch is below.

    :)>

    Attachment image
  • 1 month ago

    Since the circle is tangent to x axis, the center must be right above or right below the point (2, 0).  So the center is at (2, 3) or (2, -3).

    (x - x[center])^2 + (y - y[center])^2 = radius^2

    I leave it up to you to plug in the numbers.

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