If the point (10, 12) is on the graph of the function y = f(x), what point must be on the graph of y = -2f^-1(-x)+1?

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  • Pope
    Lv 7
    1 month ago
    Favourite answer

    f(10) = 12

    f⁻¹(12) = 10

    f⁻¹[-(-12)] = 10 ... if f⁻¹ exists

    -2f⁻¹[-(-12)] = -20

    -2f⁻¹[-(-12)] + 1 = -19

    -19 = -2f⁻¹[-(-12)] + 1

    The point (-12, -19) satisfies y = -2f⁻¹(-x) + 1.

    Again, this depends on function f actually having an inverse, and that was not given.

  • alex
    Lv 7
    1 month ago

    Hint:

    (12, 10) is in y=f^-1(x)

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