Find the ratio of successive terms. Write your answer as a fully simplified fraction. For n≥24,?

i have limited time please help

Attachment image

1 Answer

Relevance
  • I showed you how to do it already

    (4^(n + 1) / (2 * (n + 1))!) / (4^n / (2n)!) =>

    4^(n + 1) * (2n)! / (4^n * (2n + 2)!) =>

    4 * 4^(n) * (2n)! / (4^n * (2n + 2) * (2n + 1) * (2n)!) =>

    4 / ((2n + 2) * (2n + 1)) =>

    4 / (2 * (n + 1) * (2n + 1)) =>

    2 / (n + 1) * (2n + 1) =>

    2 / (2n^2 + 3n + 1)

    The limit as n goes to infinity is 0

Still have questions? Get answers by asking now.