# Find the ratio of successive terms. Write your answer as a fully simplified fraction. For n≥24,?

i have limited time please help

### 1 Answer

Relevance

- 3 months ago
I showed you how to do it already

(4^(n + 1) / (2 * (n + 1))!) / (4^n / (2n)!) =>

4^(n + 1) * (2n)! / (4^n * (2n + 2)!) =>

4 * 4^(n) * (2n)! / (4^n * (2n + 2) * (2n + 1) * (2n)!) =>

4 / ((2n + 2) * (2n + 1)) =>

4 / (2 * (n + 1) * (2n + 1)) =>

2 / (n + 1) * (2n + 1) =>

2 / (2n^2 + 3n + 1)

The limit as n goes to infinity is 0

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