Anonymous

# Laplace transforms using shortcuts L{(2t+1)^2*e^6t}?

L{(2t+1)^2*e^6t}

### 2 Answers

Relevance

- VamanLv 71 month agoFavourite answer
L{(2t+1)^2*e^6t}?= L(4t^2+4t+1)exp 6t. Laplace transform of exp 6 t is integral exp -st+6t= 1/(s-6). Differentiate wrt 6. L(t exp 6t)= 1/(s-6)^2

Once more. You get t^2 exp 6t =2/(s-6)^3. Put these values. You get the answer. 8/(s-6)^3+4/(s-6)+1/s. I think that this is the answer.

Still have questions? Get answers by asking now.