Anonymous asked in Science & MathematicsMathematics · 1 month ago

Laplace transforms using shortcuts L{(2t+1)^2*e^6t}?


2 Answers

  • Vaman
    Lv 7
    1 month ago
    Favourite answer

    L{(2t+1)^2*e^6t}?= L(4t^2+4t+1)exp 6t. Laplace transform of exp 6 t is integral exp -st+6t= 1/(s-6). Differentiate wrt 6. L(t exp 6t)= 1/(s-6)^2

    Once more. You get t^2 exp 6t =2/(s-6)^3. Put these values. You get the answer.  8/(s-6)^3+4/(s-6)+1/s. I think that this is the answer.

  • 1 month ago


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