At a certain temperature, 0.920 mol SO3 is placed in a 3.50 L container.
At equilibrium, 0.170 mol O2 is present. Calculate 𝐾c.
- Anonymous2 months ago
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- jacob sLv 72 months ago
At a certain temperature, 0.920 mol of SO3 is placed in a 3.50-L container.
2SO3(g) <---> 2SO2(g)+O2(g)
At equilibrium, 0.170 mol of O2 is present. Calculate Kc.
[SO3] = 0.92/3.5 = 0.26285M
[SO2] = 0
[O2] = 0
[SO3] = 0.26285 - 2x
[SO2] = 0 +2x
[O2] = 0 + x = 0.170/3.5 = 0.04857
x = 0.04857
[SO3] = 0.26285 - 2*0.04857 = 0.1657
[SO2] = 0 +2x = 2*0.04857 = 0.097
K = [SO2]^2[O2] / [SO3]^2
K = (0.097^2)(0.04857 )/(0.1657^2) = 0.1670
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