# Sum to 16 terms : [(1³/1)] + [(1³+2³)/(1+3)] + [(1³+2³+3³)/(1+3+5)] + .......... to 16 Terms.?

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- Anonymous4 months ago
The numerator of each term is the sum of the cubes and the denominator is the sum of the odds. Explicit formula for each term is then

(n^4/4 + n^3/2 + n^2/4) / (n^2) = n^2/4 + n/2 + 1/4

And you sum each individual series from n=1 to 16 to get 374 + 68 + 4 = 446

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