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# 2. If x, y, and z are numbers such that xy + xz = 80, what is the value of x/2(4y + 4z) - 17?

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- KrishnamurthyLv 72 months ago
If x, y, and z are numbers such that xy + xz = 80,

what is the value of x/2(4y + 4z) - 17

x(y + z) = 80

2x(y + z) - 17 = 143

- PhilipLv 62 months ago
xy+xz = 80, ie., x(y+z) = 80;

(x/2)4(y+z) -17 = 2x(y+z) - 17 = 2(80) - 17 = 143.

- PuzzlingLv 72 months ago
Factor out 4 from the parentheses:

4x/2(y + z) - 17

Then simplify 4/2 = 2:

2 * x(y + z) - 17

The part in the middle is the same as the left hand of the original equation:

x(y + z) = xy + xz = 80

So we have:

2 * 80 - 17

= 160 - 17

= 143

Answer:

143

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