Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

2. If x, y, and z are numbers such that xy + xz = 80, what is the value of x/2(4y + 4z) - 17?

3 Answers

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  • 2 months ago

    If x, y, and z are numbers such that xy + xz = 80, 

    what is the value of x/2(4y + 4z) - 17

    x(y + z) = 80

    2x(y + z) - 17 = 143

  • Philip
    Lv 6
    2 months ago

    xy+xz = 80, ie., x(y+z) = 80;

    (x/2)4(y+z) -17 = 2x(y+z) - 17 = 2(80) - 17 = 143.

  • 2 months ago

    Factor out 4 from the parentheses:

    4x/2(y + z) - 17

    Then simplify 4/2 = 2:

    2 * x(y + z) - 17

    The part in the middle is the same as the left hand of the original equation:

    x(y + z) = xy + xz = 80

    So we have:

    2 * 80 - 17

    = 160 - 17

    = 143

    Answer:

    143

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