How many mL of 6.23M strontium hydroxide is needed to titrate 842.6 ML of 8.40M acetic acid?

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  • 3 months ago

    Suppose "842.6 ML" is "842.6 mL" instead.

    Equation for the reaction:

    Sr(OH)₂ + 2CH₃COOH → Sr(CH₃COO)₂ + 2H₂O

    Mole ratio Sr(OH)₂ : CH₃COOH = 1 : 2

    Moles of CH₃COOH = (8.40 mol/L) × (842.6/1000 mL) = 7.078 mol

    Moles of Sr(OH)₂ = (7.078 mol) × (1/2) = 3.539 mol

    Volume of Sr(OH)₂ = (3.539 mol) / (6.23/1000 mol/L) = 568 mL

    ====

    OR:

    (8.40 mol CH₃COOH / 1000 mL CH₃COOH) × (842.6 mL CH₃COOH) × (1 mol Sr(OH)₂ / 2 mol CH₃COOH) × (1000 mL Sr(OH)₂ / 6.23 mol Sr(OH)₂)

    = 568 mL Sr(OH)₂

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