Alice counted 7 cycle riders and 19 cycle wheel going past her house. How many tricycle were there?

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  • 2 months ago

    By common sense, there are 2 kinds of cycles on the road; one is the bicycle the other one is tricycle. So, let

    b=the number of bicycles

    t=the number of tricycles

    b+t=7

    2b+3t=19

    =>

    2(7-t)+3t=19

    =>

    14-2t+3t=19

    =>

    t=5.

  • 2 months ago

    In doing this  kind of homework problem, state your assumptions.

    - There are only bicycle and tricycle riders.  No uniccles, adult 4-wheel pedal carts.

    - There is one, and exactly one, rider per cycle.  No tandem bikes, no riderless self-riding bicycle.

    Then if b is the number of bicycles, and t the number of tricycles,

    b + t = 7  ; total number of riders

    2b + 3t = 19  ; bike has 2 wheels, trike has 3

    You now have 2 equations in 2 unknowns.  If you need help in proceeding, I'm sure another answer will spell it out for you.

  • 2 months ago

    Alice counted 7 cycle riders and 19 cycle wheels going past her house. 

    How many tricycles were there?

    b + t = 7

    2b + 3t = 19

    t = 5 

  • Tom
    Lv 7
    2 months ago

    6   as 3X6 is 18  The seventh rider was on a Unicycle.

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  • 2 months ago

    2*2+5*3=4+15=                      .19

  • 2 months ago

    if bicycles, and tricycles:     2..... bicycles = 4 wheels.....5 tricycles= 15  wheels...…,  4 wheels plus 15 wheels= 19 wheels......answer is 5

  • 2 months ago

    5 tricycles and 2 bicycles

  • Ian H
    Lv 7
    2 months ago

    Assuming only numbers of bicycles b and tricycles t present.

    2b + 3t = 19

    b + t = 7

    tricycles t = 5

  • 2 months ago

    Method 1: Linear equation with one unknown

    Let n be the number of tricycles.

    Then, the number of bicycles = (7 - n)

    Total number of wheels:

    3n + 2(7 - n) = 19

    3n - 14 - 2n = 19

    n = 5

    There were 5 tricycles.

    ====

    Method 2: Simultaneous equations with two unkowns

    Let x be the number of tricycle, and y be the number of bicycle.

    x + y = 7 …… [1]

    3x + 2y = 19 …… [2]

    [1] * 2:

    2x + 2y = 14 …… [3]

    [2] - [3]:

    (3x + 2y) - (2x + 2y) = 19 - 14

    n = 5

    There were 5 tricycles.

  • 2 months ago

    Six tricycles and a unicycle.

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