Anonymous
Anonymous asked in Science & MathematicsMathematics · 3 weeks ago

Systems of equation word problem? ?

Jen butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $98. Two adults and three children must pay $69. Find the price of the adult’s ticket and the price of a child’s ticket. 

16 Answers

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  • John
    Lv 4
    3 weeks ago

    if jen sits on my lap the whole way she rides for free. how does thst calculate in?

  • Ian H
    Lv 7
    3 weeks ago

    3a + 4c = 98 ..... r

    2a + 3c = 69 ..... s

    c = 3s – 2r = 11

    a = (69 – 33)/2 = 18

  • 3 weeks ago

    let x - adults 

     y - children

    3[3x + 4y = 98] eq1

     4[2x + 3y = 69]  eq2

    --------------------

    9x + 12y = 294

     -[8x + 12y = 276]

    ----------------------

    x = 18 

    solving for y from eq1

    3x + 4y = 98

     3(18) + 4y = 98

     54 + 4y = 98

     4y = 98 - 54

     4y = 44

    y = 11

    The price of the adults tickets is $18 and price of children ticket is $11...

  • RR
    Lv 7
    3 weeks ago

    Three adults and four children must pay $98.

    (i) 3a + 4c = 98

    Two adults and three children must pay $69.

    (ii) 2a + 3c = 69

    You need to eliminate one unknown by making them equal in both equations and subtracting one from the other:

    (i) x 2

    = (iii) 6a + 8c = 196

     and (ii) x 3

    = (iv) 6a + 9c = 207

    subtract (iii) from (iv)

    c = 11

    substitute into (i)

    3a + (4 x 11) = 98

    3a + 44 = 98

    3a = 54

    a = 18

    ANS Adult = $18

    , Child = $11

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  • 3 weeks ago

    adults pay $32.66, kids pay $10.89.

    basic maths 98 dived by 3 , gives you the price per adult , multiply by 2 aduts , left over divided by 3 kids gives you the price per kid.

  • 3 weeks ago

      3a + 4c = 98

      2a + 3c = 69

      6a + 8c = 196

      6a + 9c = 207

      c = 11, a = 18

      The price of an adult’s ticket is $18

      and the price of a child’s ticket is $11.

  • sepia
    Lv 7
    3 weeks ago

     Jen butler has been pricing Speed-Pass train fares 

     for a group trip to New York.   

     Three adults and four children must pay $98. 

     Two adults and three children must pay $69. 

     3a + 4c = 98

     2a + 3c = 69

     6a + 8c = 196

     6a + 9c = 207

     c = 11, a = 18

     The price of an adult’s ticket is $18

     and the price of a child’s ticket is $11.

  • 3 weeks ago

    3A + 4C = 98

    2A +3C = 69

    SUBTRACT

    A + C = 29

    MULTIPLY BY 3

    3A + 3C = 87

    SUBTRACT FROM EQUATION 1

    C = 11

    SUBSTITUTE VALUE OF C IN ANY EQUATION

    A = 18

    ANSWER  ADULT = $18   CHILD = $11

  • 3 weeks ago

    let price of adult ticket = $ x

    price of child ticket = $ y

    3 adults and 4 children must pay $ 98

    so equation becomes

    3x + 4y = 98

    2 adults and 3 children must pay $ 69

    equation becomes

    2x + 3y = 69

    solving the two equations for x and y

    In this case multiply 1st equation by 2 and 2nd equation by 3

    6x + 8y =196

    6x + 9y =207

    Subtract the 1st from the second .

    y= 11

    x= 18

    $18.00 for adults 

    $ 11.00 for child

  • 3 weeks ago

    3a + 4c = 98

    2a + 3c = 69

    multiply first by 2, second by –3 and add

    6a + 8c = 196

    –6a – 9c = 207

    –c = –11

    c = 11

    2a + 3c = 69

    2a + 3•11 = 69

    2a + 33 = 69

    2a  = 36

    a = 18

    check

    3a + 4c = 98

    3•18 + 4•11 = 98

    54 + 44 = 98 ok

    2a + 3c = 69

    2•18 + 3•11 = 69

    36 + 33 = 69 ok

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