Find 𝑔′(4) given that 𝑓(4)=βˆ’2 and 𝑓′(4)=4?

(a) For 𝑔(π‘₯)=3π‘₯2βˆ’5𝑓(π‘₯)

𝑔′(4) = 4

(b) For 𝑔(π‘₯)=2π‘₯+1/𝑓(π‘₯)

𝑔′(4) = ?

I know that my answer to (a) is right, but I'm confused on why (b) isn't 1/2?

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