# How to graph the linear equation -x+2y=-1?

### 4 Answers

- lenpol7Lv 71 month ago
Re-write the equation in the form y = mx + c

2y = x - 1

y = x/2 - 1/2

Hence the line has a y-intercept at '-1/2' and a slope of '1/2'

Further two points when y = 0 (intercepts the x-axis)

then x/2 = 1/2

x = 1

So coordinate points are

(0, -1/2) and ( 1, 0)

- Engr. RonaldLv 71 month ago
Assign some value of x to solve for y to get their ordered pair.

example

1st we make the equation into slope intercept form format.

- x + 2y = - 1

2y = x - 1

y = 1/2x - 1/2

Our slope is m = 1/2 and y - intercept = - 1/2

now let us solve its ordered pair by assigning value of x.

when x = 1

y = 1/2(1) - 1/2 = 0 ordered pair is (1,0)

The graph of the equation can be seen here:

- ?Lv 71 month ago
-x+2y=-1

// Choose 2 points P₁ and P₂on the line.

When x = 0,

..........-(0) + 2y = -1

..........y = -½

..........So P₁ = (0, -½)

When y = 0,

..........-x + 2(0) = -1

..........-x = -1

..........x = 1

..........So P₂ = (1, 0)

Plot points P₁ = (0, -½) and P₂ = (1, 0)

Then, draw a line through the points.

- llafferLv 71 month ago
There are many ways of doing it. One way is to use the intercepts:

-x + 2y = -1

Solve for x when y = 0 and solve for y when x = 0:

-x + 2(0) = -1 and -0 + 2y = -1

-x + 0 = -1 and 2y = -1

-x = -1 and 2y = -1

x = 1 and y = -1/2

So you now have two points: (1, 0) and (0, -1/2)

Plot them in a grid and draw the line that connects them.