Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

How to graph the linear equation -x+2y=-1?

4 Answers

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  • 1 month ago

    Re-write the equation in the form y = mx + c 

    2y = x - 1

    y = x/2 - 1/2 

    Hence the line has a y-intercept at '-1/2' and a slope of '1/2' 

    Further two points when y = 0 (intercepts the x-axis) 

    then x/2 = 1/2 

    x = 1

    So coordinate points are 

    (0, -1/2) and ( 1, 0) 

  • 1 month ago

    Assign some value of x to solve for y to get their ordered pair.

    example

    1st we make the equation into slope intercept form format.

     - x + 2y = - 1

     2y = x - 1

      y = 1/2x - 1/2

    Our slope is m = 1/2 and y - intercept = - 1/2

    now let us solve its ordered pair by assigning value of x.

    when x = 1

    y = 1/2(1) - 1/2 = 0 ordered pair is (1,0)

    The graph of the equation can be seen here:

    https://www.wolframalpha.com/input/?i=graph+-x%2B2...

  • ?
    Lv 7
    1 month ago

    -x+2y=-1

    // Choose 2 points P₁ and P₂on the line.

    When x = 0,

    ..........-(0) + 2y = -1

    ..........y = -½

    ..........So P₁ = (0, -½)

    When y = 0,

    ..........-x + 2(0) = -1

    ..........-x = -1

    ..........x = 1

    ..........So P₂ = (1, 0)

    Plot points P₁ = (0, -½) and P₂ = (1, 0)

    Then, draw a line through the points.

  • 1 month ago

    There are many ways of doing it.  One way is to use the intercepts:

    -x + 2y = -1

    Solve for x when y = 0 and solve for y when x = 0:

    -x + 2(0) = -1 and -0 + 2y = -1

    -x + 0 = -1 and 2y = -1

    -x = -1 and 2y = -1

    x = 1 and y = -1/2

    So you now have two points: (1, 0) and (0, -1/2)

    Plot them in a grid and draw the line that connects them.

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