Anonymous
Anonymous asked in Science & MathematicsChemistry · 3 weeks ago

Help? If E°r for the reaction Zn^2+ (aq) + 2e- --> Zn(s) is -0.76V, which of the following are able to oxidize Zn(s)?

If E°r for the reaction Zn^2+ (aq) + 2e- --> Zn(s) is -0.76V, which of the following are able to oxidize Zn(s)?

I. Fe^2+ (aq) + 2e- --> Fe (s) , E°r = -0.45V

II. I (s) + 2e- --> 2I- (aq) ,  E°r = +0.54V

III. 2H+ (aq) + 2e- --> H2 (g) , E°r = 0.00V

IV. Al^3+ (aq) + 3e- --> Al (s) , E°r = -1.66V

The following answer options:

a) I and III

b) II and III

c) I and IV

d) I, II, and III

1 Answer

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  • 3 weeks ago
    Favourite answer

    d) I, II, and III

    The potential for the oxidiation of Zn --> Zn2+ + 2 e- E°= +0.76

    As long as the other half reaction has a potential greater than -0.75, the overall reaction will be spontaneous. So, I, II and III will all give spontaneous reactions. IV will not as the cell potential as written would be - 0.90 V

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