Anonymous
Anonymous asked in Science & MathematicsMathematics · 4 weeks ago

Show that each function is a solution to the IVP. On what interval is the solution de ned? (1) y0 = 1 + y2; y(pie) = 0; y = tan(x):?

Show that each function is a solution to the IVP. On what interval is the solution de ned?

(1) 

y0 = 1 + y2;

y(pie) = 0;

y = tan(x):

(2)

y0 = y2 + 4;

y(0) = 0:

y = 2 tan (2x) :

3 Answers

Relevance
  • rotchm
    Lv 7
    4 weeks ago

    Hints: 

    - Learn to COPY EXACTLY the question as it is given to you.

    - π <> pie. LEARN the correct language.

    -Un-anon yourself since its very impolite to be anon.

    - ...

    Dont forget to vote (me?) BA for this valuable advice!

  • Anonymous
    4 weeks ago

    Meaningless.  You have given no differential equations and what you have given is ambiguous.

    Also π is written as 'pi', not 'pie' and there is no such word as 'dened'.

    Well done!

  • ted s
    Lv 7
    4 weeks ago

    WHERE IS THE IVP ?

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