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# Calculating chance with repeated action and multiple changing variables?

Let's say I have a deck of 60 cards, with 6 jokers. If I draw 6 cards, what's the chance of getting all 6 if I repeat the action 6 times? It is my understanding that since we have to assume each draw will net a joker, meaning one less joker the next and one less card in the deck, the math goes like this:

(6/60) (5/59) (4/58) (3/57) (2/56) (1/55) = .0000000199744886 = 00000199744886%

Am I right? If not, please help me fix my reasoning.

### 1 Answer

Relevance

- Jeff AaronLv 74 weeks ago
If you draw 6 cards, yes, the chance of getting all 6 jokers is 1/C(60,6)

= 1/50,063,860=~ 0.000000019974488583181560510915458776051

If you do the above experiment 6 times, the chance of getting 6 jokers every time is (1/50,063,860)^6 =~ 6.3511740140772551086345793823987 * 10^(-47)

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