What is the maximum mass of methane (CH4) that can be burned if only 1.0 g of oxygen is available?
- Roger the MoleLv 71 month ago
The other answerers are correct if you suppose the methane must be burnt completely.
But since this question seems to want to burn the most possible amount of methane, incomplete combustion must be considered as well:
2 CH4 + 3 O2 → 2 CO + 4 H2O
(1.0 g O2) / (31.99886 g O2/mol) x (2 mol CH4 / 3 mol O2) x (16.0425 g CH4/mol) =
0.33 g CH4
- davidLv 71 month ago
CH4 + 2O2 --> CO2 + 2H2O
1.0 X 16/64 = 0.25g methane
- 1 month ago
CH4 + 2 O2 = CO2 + 2 H2O
if we have 1 g of O2 we have (1g // 32 g / mol ) moles of O2 = 0.03125 moles
these react with 0.03125 / 2 moles of CH4 = 0.0156 moles
mass of these moles = 0.0156 moles * 16 g / mol = 0.25 g of methane