What is the maximum mass of methane (CH4) that can be burned if only 1.0 g of oxygen is available?

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  • 1 month ago

    The other answerers are correct if you suppose the methane must be burnt completely.

    But since this question seems to want to burn the most possible amount of methane, incomplete combustion must be considered as well:

    2 CH4 + 3 O2 → 2 CO + 4 H2O

    (1.0 g O2) / (31.99886 g O2/mol) x (2 mol CH4 / 3 mol O2) x (16.0425 g CH4/mol) =

    0.33 g CH4

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  • david
    Lv 7
    1 month ago

    CH4  +  2O2  -->  CO2  +  2H2O

       1.0  X  16/64   =  0.25g methane

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  • 1 month ago

    CH4 + 2 O2 = CO2 + 2 H2O 

    if we have 1 g of O2 we have (1g // 32 g / mol )   moles of O2 =  0.03125 moles

    these react with 0.03125 / 2 moles of CH4 = 0.0156 moles 

    mass of these moles = 0.0156 moles * 16 g / mol = 0.25 g of methane 

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