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# How do you write this as a rectangular equation by eliminating the parameter? I am not sure where to go about the sin(2t) thank you?

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- PhilipLv 61 month ago
x = 4sin(2t).

y = 2cos(2t).

(x/4) = sin(2t).

(y/2) = cos(2t).

(x/4)^2 = sin^2(2t).

(y/2)^2 = cos^2(2t).

(x/4)^2 + (y/2)^2 = sin^2(2t) + cos^2(2t) = 1.

(x/4)^2 + (y/2)^2 = 1.

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- davidLv 71 month ago
x^2 = 16sin^2(2t) >>> x^2 / 16 = sin^2(2t)

y^2 = 4cos^2(2t) >>> y^2 / 4 = cos^2(2t)

. . . . . ADD >>>>>> x^2 / 16 + y^2 / 4 = 1 <<< answer

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- 1 month ago
x/4 = sin(2t)

y/2 = cos(2t)

(x/4)^2 = sin(2t)^2

(y/2)^2 = cos(2t)^2

(x/4)^2 + (y/2)^2 = sin(2t)^2 + cos(2t)^2

(x/4)^2 + (y/2)^2 = 1

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