A 6.72 g sample of zinc was placed in 100 mL of 1.50 mol/L hydrochloric acid. After the reaction stops, how much zinc should remain?
- Anonymous1 month ago
Balanced equation is Zn + 2HCl = ZnCl2 + H2
moles of HCl = 0.1 L * 1.5 mole/L = 0.15 mole. From the balanced equation, moles of Zn that react = 1/2 the moles of HCl. Mass of Zn that reacts = moles of Zn * atomic mass
mass of Zn remaining = 6.72 g - mass of Zn that reacts.