# Chemistry problem I just can't solve! Help!?

A graduated cylinder is filled to the 40.00−mL mark with a mineral oil. The masses of the cylinder before and after the addition of the mineral oil are 124.966 g and 159.446 g, respectively. In a separate experiment, a metal ball bearing of mass 19.836 g is placed in the cylinder and the cylinder is again filled to the 40.00−mL mark with the mineral oil. The combined mass of the ball bearing and mineral oil is 50.952 g. Calculate the density and radius of the ball bearing (volume of a sphere of radius r is 4/3πr3).

### 1 Answer

- Dr WLv 72 months ago
in the first cylinder you have

.. 40.00mL mineral oil

.. mass mineral oil = (159.446g - 124.966g) = 34.480g

in the second cylinder

.. mass ball bearing = 19.836g

.. mass mineral oil = 50.952g - 19.836g = 31.116g

you want density of ball bearing..

you already have mass of bearing

you need volume of ball bearing to finish

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solution

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volume bearing

.. V bearing = Vtotal - Voil

.. .. .. ... .. . = 40.00mL - 31.116g * (40.00mL / 34.480g)

.. ... .. ... ... .= __ mL

then

.. density bearing = 19.836g / __mL = __ g/mL

as to radius

.. V = 4/3 * π * r³

.. r = ³ √( 3*V / (4π))

.. r = ³ √( 3*3.902cm³ / (4π)) = __ cm

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YOU fill in the blanks

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you seem to have quite a few "chemistry problems that you can't solve". Are you actually trying?

look at this problem you posted. https://answers.yahoo.com/question/index?qid=20200530234949AATUsdW convince me that YOU tried to solve it on your own.