Chemistry problem I just can't solve! Help!?

A graduated cylinder is filled to the 40.00−mL mark with a mineral oil. The masses of the cylinder before and after the addition of the mineral oil are 124.966 g and 159.446 g, respectively. In a separate experiment, a metal ball bearing of mass 19.836 g is placed in the cylinder and the cylinder is again filled to the 40.00−mL mark with the mineral oil. The combined mass of the ball bearing and mineral oil is 50.952 g. Calculate the density and radius of the ball bearing (volume of a sphere of radius r is 4/3πr3).

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  • Dr W
    Lv 7
    2 months ago

    in the first cylinder you have

    .. 40.00mL mineral oil

    .. mass mineral oil = (159.446g - 124.966g) = 34.480g

    in the second cylinder

    .. mass ball bearing = 19.836g

    .. mass mineral oil = 50.952g - 19.836g = 31.116g

    you want density of ball bearing.. 

    you already have mass of bearing

    you need volume of ball bearing to finish

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    solution

    *********

    volume bearing

    .. V bearing = Vtotal - Voil

    .. .. .. ... .. .  = 40.00mL - 31.116g * (40.00mL / 34.480g)

    .. ... .. ... ... .= __ mL 

    then

    .. density bearing = 19.836g / __mL = __ g/mL

    as to radius

    .. V = 4/3 * π * r³

    .. r = ³ √( 3*V / (4π))

    .. r = ³ √( 3*3.902cm³ / (4π)) = __ cm

    *********

    YOU fill in the blanks

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    *********

    you seem to have quite a few "chemistry problems that you can't solve".  Are you actually trying?

    • ...Show all comments
    • Dr W
      Lv 7
      1 month agoReport

      look at this problem you posted. https://answers.yahoo.com/question/index?qid=20200530234949AATUsdW  convince me that YOU tried to solve it on your own. 

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