54. Identify the center of the parabola (y + 5)2 = 8x − 4.?

54) Identify the center of the parabola (y + 5)2 = 8x − 4.

okay so is it asking for vertex? is center same as vertex in which i got (1/2 , -5) ?

5 Answers

Relevance
  • 7 months ago
    Favourite answer

    (y + 5)^2 = 8x − 4

    (y + 5)^2 + 4 = 8x

    x = 1/8(y + 5)^2 + 1/2

    yeh, it's (1/2, - 5)

    This will be the graph look like.

    Attachment image
  • 7 months ago

    Note that parabola has no center! you got a

    right answer but it was the vertex, not the center.

  • Pope
    Lv 7
    7 months ago

    No, of course the vertex is not the center. A parabola has no center, but the curve is a limiting case of a hyperbola or ellipse. It sometimes is useful to employ a special definition allowing the center to be a point at infinity. In this case it would be the point at infinity on the line y + 5 = 0.

    It would be better though simply to answer that the parabola has no center. Do not change the question to suit the answer. You were not asked for the vertex.

  • 7 months ago

    (y + 5)^2 = 8 x - 4

    parabola

    focus | (5/2, -5) = (2.5, -5)

    vertex | (1/2, -5) = (0.5, -5)     <----

    semi-axis length | 2

    focal parameter | 4

    eccentricity | 1

    directrix | x = -3/2

  • What do you think of the answers? You can sign in to give your opinion on the answer.
  • DWRead
    Lv 7
    7 months ago

    (y+5)² = 8x-4

    8x = (y+5)² + 4

    x = ⅛(y+5)² + ½

    This is a horizontal parabola with vertex (½,-5).

    Axis of symmetry: y = -5

Still have questions? Get answers by asking now.