Anonymous
Anonymous asked in Science & MathematicsMathematics · 4 weeks ago

# Help needed with a probability question, please?

Four teams Antwerp, Brindisi, Cadiz and Dortmund are left in the championship. One (and only one) of the teams can win the trophy. Antwerp is twice as likely to win as Brindisi, Brindisi is three times as likely to win as Cadiz and Cadiz are twice as likely to win as Dortmund.

What are the teams respective probabilities of winning?

What is the probability that neither Brindisi nor Cadiz wins?

Relevance

Let a, b, c and d be the probabilities that Antwerp, Brindisi, Cadiz and Dortmund win the trophy respectively.

a + b + c + d = 1 …. 

a = 2b …… 

b = 3c …… 

c = 2d …… 

Substitute  into :

b = 3(2d)

b = 6d …… 

Substitute  into :

a = 2(6d)

a = 12d …… 

Substitute ,  and  into :

12d + 6d + 2d + d = 1

21d = 1

d = 1/21

P(Antwerp wins) = 12 × (1/21) = 4/7

P(Brindisi wins) = 6 × (1/21) = 2/7

P(Cadiz wins) = 2 × (1/21) = 2/21

P(Dortmund wins) = 1/21

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