When a mixture of 13.0 g of acetylene (C2H2) and 13.0 g of oxygen (O2) is ignited, the resultant combustion reaction produces CO2 and H2O.?
Which is the Limiting Reactant? Express in Chemical formula.
- Roger the MoleLv 71 month ago
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
(13.0 g C2H2) / (26.0373 g C2H2/mol) = 0.499284 mol C2H2
(13.0 g O2) / (31.99886 g O2/mol) = 0.406264 mol O2
0.406264 mole of O2 would react completely with 0.406264 x (2/5) = 0.1625056 mole of C2H2, but there is more C2H2 present than that, so C2H2 is in excess and O2 is the limiting reactant.