# Geometry-rotations?

If the diameter of the moon is 3475 km and an orbiting space station is circling 21 km above the lunar surface, find the distance traveled by the lunar station in one orbit.

Relevance
• 3 weeks ago

D = diameter of moon = 3,475 km

r1 = radius of moon = D / 2 = 1,738 km

h = orbital height of space station = 21 km

r2 = orbital radius = r1 + h = 1,759 km

C = orbital circumference = to be determined

C = 2πr

C = 2(3.14159)(1,759 km)

C = 11,049 km

• Anonymous
4 weeks ago

Source(s): Women wear headscarves tied at the front to prevent headaches from sky pushing down and to prevent throat cancer. Mega-tsunami for New York will be 400 meters; then engulfed-in-lava Los Angeles will be flooded too; also, asteroid destroys Gulf of Mexico; only Alaska, Eurasia, and Africa remain (obviously without coasts). 1st big earthquake in Russia; 2nd bigger one in China (will be split in half; radiation!); 3rd biggest will be in the USA (Greek Orthodox monk Elidiy from Africa); forgive me.
• 1 month ago

Some questions suggest ,just sheer laziness

• 1 month ago

Pi times Diameter , plus twice Altitude is 10, 520.14 kms

• 1 month ago

Diameter of the orbit, d

= (3475 + 21×2) km

= 3517 km

Distance traveled in one orbit

= π d

= 3.1416 × 3517 km

= 11050 km (to 4 sig. fig.)