The arm of a crane at a construction site is?
17.0 m long, and it makes an angle of 17.0
with the horizontal. Assume that the maximum load the crane can handle is limited
by the amount of torque the load produces
around the base of the arm.
What maximum torque can the crane withstand if the maximum load the crane can
handle is 672 N?
Answer in units of N · m.
2. What is the maximum load for this crane at
an angle of 26.0
◦ with the horizontal?
Answer in units of N.
- Anonymous1 month ago
If the 672 N (that's a REALLY small load for a crane) applies to the 17 deg angle then the maximum torque = 672 N * cos 17 deg * 17 m
For the second part, do it the same way as above.