Anonymous
Anonymous asked in Science & MathematicsChemistry · 8 months ago

How many moles of nickel II chloride should be added to 600. moles of water to lower its vapor pressure from 360 torr to 351 torr?

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  • 8 months ago
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    Let y mol be the no. of moles of NiCl₂ (nickel(II) chloride) added.

    Each mole of NiCl₂ contains 1 mole of Ni²⁺ ions and 2 moles of Cl⁻ ions.

    Number of moles of ions present in the solution = (1 + 2)y mol = 3y mol

    P(water) = X(water) * P(water)°

    351 torr = [600/(600 + 3y)] * (360 torr)

    351 (600 + 3y) = 600 * 360

    210600 + 1053y = 216000

    1053y = 5.13

    No. of moles of NiCl₂ added = 5.13 mol

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