Anonymous
Anonymous asked in Science & MathematicsChemistry · 2 months ago

If you started with 5.0 L of a 0.25 M solution of xenon trioxide, and you isolated 24 g of oxygen, what is your percent yield?

Balanced equation: 2 XeO3 ----> 2 Xe + O3

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  • 2 months ago

    The equation shown is not balanced.  I think it's supposed to be:

    2 XeO3 → 2 Xe + 3 O2

    (5.0 L) x (0.25 mol XeO3 / L) x (3 mol O2 / 2 mol XeO3) x (31.99886 g O2/mol) = 59.9978 g O2 in theory

    (24 g) / (59.9978 g) = 0.40001 = 40.% yield O2

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