Trigonometri Cos Tan Sin challange?

Find :

1.Angle v

2.Lenghth of CB and AC

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2 Answers

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  • 4 weeks ago

    Answer is a bit long as I’ve tried to explain fully. 

     

    1. Call the bottom right-hand corner P.  You have a large right-angled triangle, ABP. 

    Hypotenuse  AB= 60m.  Side opposite angle v = BP = 12m. 

     

    sin(v) = BP/AB = 12/60 = 0.2 

     

    v = sin⁻¹(0.2) 

    , .= 11.54º 

    (Note, your calculator must be set to degrees mode, not radians mode.) 

    ______________ 

     

    2.  In triangle BCP: 

    sin(30º) = BP/BC = 12/BC 

    BC = 12/sin(30º) = = 12/(0.5) = 24m 

     

    There are several ways to find AC. Here’s one using the sine rule in triangle ABC (see link) 

     

    ∠ABC = 180º – 150º -  11.54º = 18.46º 

     

    24/sin(11.54º) = AC/sin(18.46º) 

    AC = 24sin(18.46º)/sin(11.54º) 

    . . . = 38m 

     

  • 4 weeks ago

    60 sinv = 12, sinv = 1/5 and v = 11.54 deg.

    12/CB = sin 30 = 1/2, CB = 24 m,

    AC = 60 cosv - 12/tan30 = 60 cos11.54 - 12/tan30 = 38 m

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