7th grade science urgent! begging for help!?
In a series circuit, there are 12 light bulbs, each providing 1 ohm of resistance. What is the total resistance?
- PhilomelLv 711 months ago
- RAGHAVENDRANLv 411 months ago
In a series circuit, resistance is added. So the requried answer=1Ohm×12=12Ohm.
- Anonymous11 months ago
Series resistance is additive.
1Ω × 12 = 12Ω
Twelve 1Ω resistors in series is 12Ω resistance.Source(s): Been there
- frank lynnLv 611 months ago
In a series circuit, that means the light bulbs are connected one after the other, resistances are added. In this case with twelve identical resistances of 1 Ohm, we can more easily say 12 x 1 Ohm = 12 Ohms.
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- ElleLv 712 months ago
What makes it "urgent?" Are you choking? Bleeding? Out of time?
Miss planning on your part does NOT constitute an urgent/emergency on our's.
- oubaasLv 712 months ago
Rtot = 1*12 = 12 ohm
- electron1Lv 712 months ago
When light bulbs are in series, the total resistance is the sum of the resistances. This is 12 ohms.
- Anonymous12 months ago
Looks like somebody is going to flunk 7th grade science.
You don’t know how to add? It’s 12. There are 12 bulbs with 1 ohm of resistance in a series. In a series, you just add the resistance. In a parallel circuit, you add the inverse.
- Red FoxLv 712 months ago
The total resistance of a series circuit is equal to the sum of individual resistances.
In a series circuit you will need to calculate the total resistance of the circuit in order to figure out the amperage. This is done by adding up the individual values of each component in series.
In this example we have three resistors. To calculate the total resistance we use the formula:
RT = R1 + R2 + R3
2 + 2 + 3 = 7 Ohms
R total is 7 Ohms
Now apply this to your problem. 🙂