Woger asked in Science & MathematicsMathematics · 8 months ago

# Inaclubthereare1womenand 7 men. A committee of 5 women and 3 men is to be chosen. How many different ways are there to select the committee?

Update:

In a club there are 11 women and 7 men. A committee of 5 women and 3 men is to be chosen. How many different ways are there to select the committee?

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• Anonymous
8 months ago

1 women?

I don't think so.

• 8 months ago

In a club there are 11 women and 7 men.

A committee of 5 women and 3 men is to be chosen.

The number of different ways to select the committee:

11C3 × 7C3 = 5,775

• 8 months ago

Updated question: "In a club there are 11 women and 7 men. A committee of 5 women and 3 men is to be chosen. How many different ways are there to select the committee?"

From the 11 women, choose 5

C(11,5) = (11 * 10 * 9 * 8 * 7) / (5 * 4 * 3 * 2 * 1)

= 462

From the 7 men, choose 3

C(7,3) = (7 * 6 * 5) / (3 * 2 * 1)

= 35

Multiply these together to get the total number of possible committees.

462 * 35

= 16,170 ways

• 8 months ago

Different ways of selection = 11C5 + 7C3 = 11!/(6!)(5!) + 7!/(4!)(3!) = 497.

• 8 months ago

there are 11 women deleted a number by mistake