Inaclubthereare1womenand 7 men. A committee of 5 women and 3 men is to be chosen. How many different ways are there to select the committee?

Update:

In a club there are 11 women and 7 men. A committee of 5 women and 3 men is to be chosen. How many different ways are there to select the committee?

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  • Anonymous
    4 weeks ago

    1 women?

    I don't think so.

  • 4 weeks ago

    In a club there are 11 women and 7 men.

    A committee of 5 women and 3 men is to be chosen.

    The number of different ways to select the committee:

    11C3 × 7C3 = 5,775

  • 4 weeks ago

    Updated question: "In a club there are 11 women and 7 men. A committee of 5 women and 3 men is to be chosen. How many different ways are there to select the committee?"

    From the 11 women, choose 5

    C(11,5) = (11 * 10 * 9 * 8 * 7) / (5 * 4 * 3 * 2 * 1)

    = 462

    From the 7 men, choose 3

    C(7,3) = (7 * 6 * 5) / (3 * 2 * 1)

    = 35

    Multiply these together to get the total number of possible committees.

    462 * 35

    = 16,170 ways

  • 4 weeks ago

    Different ways of selection = 11C5 + 7C3 = 11!/(6!)(5!) + 7!/(4!)(3!) = 497.

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  • 4 weeks ago

    there are 11 women deleted a number by mistake

  • ?
    Lv 7
    4 weeks ago

    There are 0 ways to get a committee with 5 women in it from a sample pool with 1 woman.

  • 4 weeks ago

    Zero! you can't have a committee with five women if there's only one woman in the club

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