A rifle is aimed horizontally at a target 45 m away. The bullet hits the target 2.5 cm below the aim point.?

a)What was the bullet's flight time? Neglect the air resistance.

b)What was the bullet's speed as it left the barrel?

3 Answers

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  • 5 months ago
    Favorite Answer

    time for an object to fall 2.5 cm or 0.025 m

    t = √(2h/g) = √(2• 0.025/9.8) = 0.0714 sec, rounded to 0.071 s

    v = d/t = 45/0.071 = 630 m/s

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  • 5 months ago

    The time it takes the bullet to reach the target is the time it takes to fall 2.5cm

    0.025 = ½gt²

    2*0.025/9.8 = t² = 0.07143²

    V = d/t = 45/0.07143 = 630m/s

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  • Anonymous
    5 months ago

    Both answers are: you don't have a license to bear arms

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