A rifle is aimed horizontally at a target 45 m away. The bullet hits the target 2.5 cm below the aim point.?
a)What was the bullet's flight time? Neglect the air resistance.
b)What was the bullet's speed as it left the barrel?
- billrussell42Lv 75 months agoFavorite Answer
time for an object to fall 2.5 cm or 0.025 m
t = √(2h/g) = √(2• 0.025/9.8) = 0.0714 sec, rounded to 0.071 s
v = d/t = 45/0.071 = 630 m/s
- oldschoolLv 75 months ago
The time it takes the bullet to reach the target is the time it takes to fall 2.5cm
0.025 = ½gt²
2*0.025/9.8 = t² = 0.07143²
V = d/t = 45/0.07143 = 630m/s
- Anonymous5 months ago
Both answers are: you don't have a license to bear arms