Adam asked in Science & MathematicsMathematics · 12 months ago

Suppose f(x) = x2 + 16x + 7. What is the x-coordinate of the larger x-intercept?

2 Answers

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  • 12 months ago

    f(x) = x² + 16x + 7 = x² + 16x + 64 - 57 = (x + 8)² - 57

    f(x) = 0 when (x + 8)² = 57 , so when x = -8 + √57 and when x = -8 - √57

    So the larger x intercept is -8 + √57, which has the coordinates (-8 + √57, 0)

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  • alex
    Lv 7
    12 months ago

    f(x)=0---> x = -8+√57

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