### 1 Answer

Relevance

- 3 years agoFavourite answer
Subtract first two giving (z-x)(x+y+z)=24 or z=x+24/s where s=x+y+z

Subtract last two giving y=x-15/s

s = x+y+z = x+(x-15/s)+(x+24/s) = 3x+9/s which gives x=(s^2-9)/(3s) and so y=(s^2-54)/(3s)

Sub in first equation for (s^2-9)^2 + (s^2-9)(s^2-54) + (s^2-54)^2 = 25(9s^2)

This boils down to (s^2-9)(s^2-129)=0 and you have your answer

Still have questions? Get answers by asking now.