JOHN
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JOHN asked in Science & MathematicsMathematics · 3 years ago

Find x + + z given that?

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  • 3 years ago
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    Subtract first two giving (z-x)(x+y+z)=24 or z=x+24/s where s=x+y+z

    Subtract last two giving y=x-15/s

    s = x+y+z = x+(x-15/s)+(x+24/s) = 3x+9/s which gives x=(s^2-9)/(3s) and so y=(s^2-54)/(3s)

    Sub in first equation for (s^2-9)^2 + (s^2-9)(s^2-54) + (s^2-54)^2 = 25(9s^2)

    This boils down to (s^2-9)(s^2-129)=0 and you have your answer

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