# Help with these algorithms .... !!!!?

1.- Given two numbers count how many divisors has the first are smaller than the second

2.- Given 2 numbers count how many dividers each has

### 2 Answers

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- husoskiLv 74 years ago
1. Just loop from k=1 to (second number)-1 and count how many values of k divide (first number) evenly.

2. Is this supposed to be common divisors? i.e. counting how many different numbers will evenly divide both input numbers? If so, just loop from k=1 to min(first, second) and count 1 each time k divides both first and second.

If you really mean problem 2 to be as stated, then simply write a divisor count procedure for a single number, then perform that procedure for each of the two input values.

- PuzzlingLv 74 years ago
Check the links below for some ideas.

Source(s): https://rosettacode.org/wiki/Proper_divisors https://rosettacode.org/wiki/Factors_of_an_integer

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