# Determine the molar solubility of MgCO3 in pure water.? Ksp = 6.8x10^-6?

I know the answer is 2.6 x 10^-3 , but can someone give me the steps to finding that answer please?

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- DavidBLv 74 years agoFavourite answer
solubility equilibria ... use an ICE table

MgCO3 <--> Mg2+ + CO3^2-

the ICE table gives

Ksp = x^2 = 6.8e-6

solve for x = [Mg2+] = [MgCO3]

assume 1 L of solution and [MgCO3] is number moles, so find mass dissolved per L

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