Determine the molar solubility of MgCO3 in pure water.? Ksp = 6.8x10^-6?
I know the answer is 2.6 x 10^-3 , but can someone give me the steps to finding that answer please?
- DavidBLv 74 years agoFavourite answer
solubility equilibria ... use an ICE table
MgCO3 <--> Mg2+ + CO3^2-
the ICE table gives
Ksp = x^2 = 6.8e-6
solve for x = [Mg2+] = [MgCO3]
assume 1 L of solution and [MgCO3] is number moles, so find mass dissolved per L