Determine the molar solubility of MgCO3 in pure water.? Ksp = 6.8x10^-6?

I know the answer is 2.6 x 10^-3 , but can someone give me the steps to finding that answer please?

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  • DavidB
    Lv 7
    4 years ago
    Favourite answer

    solubility equilibria ... use an ICE table

    MgCO3 <--> Mg2+ + CO3^2-

    the ICE table gives

    Ksp = x^2 = 6.8e-6

    solve for x = [Mg2+] = [MgCO3]

    assume 1 L of solution and [MgCO3] is number moles, so find mass dissolved per L

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